JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

Two spheres A and B of masses m₁ and m₂ respectively collide. A is at rest initially and B is moving with velocity v along the x-axis. After collision, B has velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction [CBSE PMT (Prelims) 2012]

Answer: (C)

Solution

Momentum conservation along x: m₂v = m₁vₓ. Along y: m₂(v/2) = m₁. Dividing:

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Question ID VK-153964