JEE Main Physics question
A particle of mass m at rest is acted upon by a force F for a time t. Its kinetic energy after an interval t is
Answer: (B)
Solution
Impulse = Ft = mv ⟹ v = Ft/m. KE = ½mv² = ½m(Ft/m)² = F²t²/2m.
A particle of mass m at rest is acted upon by a force F for a time t. Its kinetic energy after an interval t is
Impulse = Ft = mv ⟹ v = Ft/m. KE = ½mv² = ½m(Ft/m)² = F²t²/2m.