JEE Main Physics question

A ball is released from a certain height. It loses 50% of its kinetic energy on striking the ground. It will attain a height again equal to

Answer: (B)

Solution

Since the ball rebounds with half its kinetic energy, its rebound speed v' satisfies ½v'² = ½(½v²), i.e., v'² = v²/2.

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Question ID VK-153975