JEE Main Physics question
A force (4î + ĵ − 2k̂) N acting on a body maintains its velocity at (2î + 2ĵ + 3k̂) ms⁻¹. The power exerted is
Answer: (A)
Solution
P = F·v = (4)(2) + (1)(2) + (−2)(3) = 8 + 2 − 6 = 4 W.
A force (4î + ĵ − 2k̂) N acting on a body maintains its velocity at (2î + 2ĵ + 3k̂) ms⁻¹. The power exerted is
P = F·v = (4)(2) + (1)(2) + (−2)(3) = 8 + 2 − 6 = 4 W.