JEE Main Physics question
A force applied by an engine of a train of mass 2.05 × 10⁶ kg changes its velocity from 5 m/s to 25 m/s in 5 minutes. The power of the engine is [EAMCET 2001]
Answer: (B)
Solution
P = ΔKE/t = ½(2.05×10⁶)[(25)² − (5)²]/(5×60) = ½(2.05×10⁶)(600)/300 = 2.05×10⁶ W = 2.05 MW.