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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A car of mass 1250 kg is moving at 30 m/s. Its engine delivers 30 kW while the resistive force due to the surface is 750 N. What maximum acceleration can be given to the car?

Answer: (C)

Solution

Forward force from the engine, F = P/v = 30000/30 = 1000 N. Net force = F − R = 1000 − 750 = 250 N. a = (net force)/m = 250/1250 = 1/5 m/s².

Question ID VK-154003