JEE Main Physics question
A force of 2î + 3ĵ + 4k̂ N acts on a body for 4 seconds, and produces a displacement of (3î + 4ĵ + 5k̂) m. The power used is
Answer: (A)
Solution
W = F·d = (2)(3) + (3)(4) + (4)(5) = 6 + 12 + 20 = 38 J. P = W/t = 38/4 = 9.5 W.