JEE Main Physics question
An electric immersion heater of 1.08 kW is immersed in water. After the water has reached a temperature of 100°C, how much time will be required to produce 100 g of steam?
Answer: (A)
Solution
Latent heat to convert 1 g of water at 100°C to steam ≈ 540 cal = 540 × 4.2 =
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