JEE Main Physics question
A neutron makes a head-on elastic collision with a stationary deuteron. The fractional energy loss of the neutron in the collision is
Answer: (B)
Solution
Fractional energy loss = 1 − [(m₁−m₂)/(m₁+m₂)]², with m₁ = 1 (neutron), m₂ = 2 (deuteron): = 1 − [(1−2)/(1+2)]² = 1 − (1/9) = 8/9.