JEE Main Physics question
A canon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with a velocity 100 m/sec, the second falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocity [NCERT 1983, AFMC 1997]
Answer: (B)
Solution
At the highest point, the shell (mass m) moves horizontally with speed u cos60° = 200(0.5) = 100 m/s, so its momentum there is 100m (horizontal). After the explosion, the fragment going straight up (mass m/3, 100 m/s upward) and the one going
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