JEE Main Physics question
A body falls on a surface of coefficient of restitution 0.6 from a height of 1 m. Then the body rebounds to a height of
Answer: (D)
Solution
Height after rebound, hₙ = he^(2n) with n = 1: h₁ = 1 × (0.6)² = 0.36 m.
A body falls on a surface of coefficient of restitution 0.6 from a height of 1 m. Then the body rebounds to a height of
Height after rebound, hₙ = he^(2n) with n = 1: h₁ = 1 × (0.6)² = 0.36 m.