JEE Main Physics question
A ball is allowed to fall from a height of 10 m. If there is a 40% loss of energy due to impact, then after one impact the ball will go up to
Answer: (D)
Solution
mgh = initial PE; after a 40% loss, the remaining PE is 60% of the original: mgh' = 0.6(mgh) ⟹ h' = 0.6 × 10 = 6 m.