JEE Main Physics question
Two particles having position vectors r₁ = (3î+5ĵ) metres and r₂ = (−5î−3ĵ) metres are moving with velocities v₁ = (4î+3ĵ) m/s and v₂ = (αî+7ĵ) m/s. If they collide after 2 seconds, the value of 'α' is
Answer: (D)
Solution
The initial separation is Δr = r₂ − r₁ = (−8î − 8ĵ) m, with magnitude |Δr| = 8√2 m. For the particles to collide, their relative velocity must close this gap exactly in t = 2 s, i.e., || = |Δr|/t. The relative velocity is = v₂ − v₁ = (α−4)î + 4ĵ,
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