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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

A bullet of mass mB moving with velocity vB is fired into a block of mass M at rest on a frictionless table and gets embedded in it. Given mB = 50 g, vB = 10 m/s, and the combined system's mass is 1 kg (950 g block + 50 g bullet), the fractional (percentage) loss in kinetic energy of the system is

Answer: (B)

Solution

Initial KE of the system = KE of the bullet = ½mBvB² = ½(0.05)(10)² = 2.5 J. By momentum conservation: =

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Question ID VK-154102