JEE Main Physics question
If a skater of weight 3 kg has an initial speed 32 m/s and a second one of weight 4 kg has 5 m/s, after collision they have a common speed of 5 m/s. Then the loss in K.E. is [CPMT 1996]
Answer: (D)
Solution
Loss in KE = ½(3)(32)² + ½(4)(5)² − ½(3+4)(5)² = 1536 + 50 − 87.5 = 1498.5
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