JEE Main Physics question
A force F = −K(yî+xĵ) (where K is a positive constant) acts on a particle moving in the x-y plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) and then parallel to the y-axis to the point (a, a). The total work done by the force F on the particle is
Answer: (C)
Solution
From (0,0) to (a,0): along this path y=0, so F = −Kyî = 0 there, and the displacement is purely along x; so W₁ = 0. From (a,0) to (a,a): the displacement is purely along y (x fixed at a),
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