JEE Main Physics question
A particle of mass m moving with velocity v strikes a stationary particle of mass 2m and sticks to it. The speed of the system will be
Answer: (C)
Solution
By momentum conservation: mv = (m+2m)V ⟹ V = v/3.
A particle of mass m moving with velocity v strikes a stationary particle of mass 2m and sticks to it. The speed of the system will be
By momentum conservation: mv = (m+2m)V ⟹ V = v/3.