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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

The potential energy of a conservative system is given by V(x) = (x² − 3x) joule. Then its equilibrium position is at [Kerala PMT 2010]

Answer: (A)

Solution

For a conservative field, F = −dV/dx = −(2x−3) = −2x+3. At equilibrium, F = 0: −2x+3 = 0 ⟹ x = 1.5 m.

Question ID VK-154145