JEE Main Physics question
A body of mass 2 kg slides down a curved track which is a quadrant of a circle of radius 1 metre. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is
Answer: (A)
Solution
By energy conservation: v = √(2gh) = √(2 × 9.8 × 1) = √19.6 = 4.43 m/s.