JEE Main Physics question
A wooden block of mass M rests on a horizontal surface. A bullet of mass m, moving in the horizontal direction, strikes and gets embedded in it. The combined system covers a distance x on the surface. If the coefficient of friction between the wood and the surface is μ, the speed of the bullet at the time of striking the block is (where m is the mass of the bullet)
Answer: (C)
Solution
By momentum conservation, the combined mass (M+m) moves with speed V = mv/(M+m). By the work-energy theorem, this KE is dissipated
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account