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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A time dependent force F = 8t acts on an object of mass 2 kg. If the object starts from rest, the work done by the force during the first 4 s will be J. [JEE Main 2012]

Answer: 1024

Solution

From Newton's second law, F = ma ⟹ 2a = 8t ⟹ dv/dt = 4t. Integrating with v(0)=0: ∫₀ᵛdv = ∫₀⁴4t dt ⟹ v =

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Question ID VK-154219