JEE Main Physics question
A cricket ball of mass 180 g moving with a speed of 108 km/hr hits at the middle of the bat, held firmly at its position by the batsman. The ball moves straight back to the bowler after hitting the bat. Assuming that the collision between ball and bat is completely elastic and the two remain in contact for 0.001 s, the magnitude of the force that the batsman had to apply to hold the bat firmly at its place would be × 10³ N.
Answer: 10.8
Solution
Mass of ball m = 180 g = 0.18 kg. Initial speed u = 108 km/hr = 30 m/s. Since the collision is elastic and the ball bounces straight back with the same speed, final velocity v = −30 m/s.
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