Test SeriesFree PYQsExamsPricing

JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A body of mass 12 kg moves down the quadrant of a circle of radius 6 m. The velocity on reaching the lowest point is 6 m/s. What is the work done (in joule) against friction? (Take g = 10 m/s²)

Answer: 504

Solution

By the work-energy theorem, mgr = ½mv² + W (where W is work done against

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-154224