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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A body of 2 kg mass is initially moving along a straight line with a velocity of 1.5 m/s. A force of 4 N is applied to it at an angle of 60° to the initial direction of motion. The change in its K.E. after the first second is J.

Answer: 4

Solution

Acceleration along the direction of motion a = Fcosθ/m = (4cos60°)/2 = (4×0.5)/2 = 1 m/s². Velocity

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Question ID VK-154228