JEE Main Physics question
Assuming earth to be a sphere of uniform density, what is the value of gravitational acceleration in a mine 100 km below the earth's surface (Given km)? [AFMC 2000, Pb. PMT 2000, RPMT 2005]
Answer: (A)
Solution
$=g(1- dR)=9.8(1-)=9.8×0.9844
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