JEE Main Physics question

PhysicsMechanical Properties of SolidsJEE Main

An iron rod of length 2 m and cross-section area , stretched by 0.5 mm, when a mass of 250 kg is hung from its lower end. Young's modulus of the iron rod is [AFMC 1999]

Answer: (A)

Solution

\dfrac{MgL}{AΔ l}\dfrac{250×9.8×2}Extra open brace or missing close brace{50×10^{-6}$

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-155040