JEE Main Physics question
An iron rod of length 2 m and cross-section area , stretched by 0.5 mm, when a mass of 250 kg is hung from its lower end. Young's modulus of the iron rod is [AFMC 1999]
Answer: (A)
Solution
\dfrac{MgL}{AΔ l}\dfrac{250×9.8×2}10^{-6}$
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