JEE Main Chemistry question
The number of ions given by [Pt(NH_3)_4Cl_2]Cl_2 in aqueous solution is
Answer: $3$
Solution
[Pt(NH_3)_4Cl_2]^{2+} + 2Cl^- — 3 ions in total.
The number of ions given by [Pt(NH_3)_4Cl_2]Cl_2 in aqueous solution is
[Pt(NH_3)_4Cl_2]^{2+} + 2Cl^- — 3 ions in total.