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JEE Main Chemistry question

ChemistryChemical Bonding and Molecular StructureJEE Main

Consider: (i) H–C–H angle in methane, (ii) Cl–B–Cl angle in , (iii) F–I–F angle in (in the equatorial plane), (iv) I–I–I angle in . The increasing order of the above bond angles is

Answer: (C)

Solution

The equatorial F–I–F angle in the pentagonal bipyramidal is 72° (360°/5), the smallest of the four. The tetrahedral H–C–H angle in methane is 109.5°. The

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Question ID VK-156055