JEE Main Chemistry question

ChemistryChemical Bonding and Molecular StructureJEE Main

**Statement 1:** In , N is hybridised, but the bond angle is found to be about 107°. **Statement 2:** The decrease in bond angle (from the ideal tetrahedral 109.5°) is due to repulsion between the lone pair on nitrogen and the bond pairs between N and H.

Answer: (A)

Solution

Nitrogen in is indeed hybridised with one lone pair, giving a pyramidal shape with an observed bond angle of ≈107°, slightly less than the ideal tetrahedral angle

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-156206