JEE Main Chemistry question

ChemistryChemical Bonding and Molecular StructureJEE Main

**Statement 1:** All F–S–F angles in are greater than 90° but less than 180°. **Statement 2:** The lone pair–bond pair repulsion is stronger than the bond pair–bond pair repulsion.

Answer: (D)

Solution

has a see-saw shape (, one equatorial lone pair). The axial–equatorial F–S–F angles are actually slightly compressed to just below 90° (≈86–89°) by the lone pair, so the claim that *all* angles exceed 90° is false. The

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Question ID VK-156207