JEE Main Chemistry question
In a compound of Xe, F and O: Xe = 60.4% (atomic mass 131.3), F = 17.5% (atomic mass 19.0). Find the number of oxygen atoms in the compound.
Answer: 3
Solution
By difference, %O . Mole ratio: \dfrac{60.4}{131.3}\dfrac{17.5}{19.0}\dfrac{22.1}{16.0}$ =
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