JEE Main Physics question
The surface tension of mercury is . Its value in SI units is
Answer: (A)
Solution
32\,dyne\,cm^{-1}=\dfrac{32\times10^{-5}\,N}{10^{-2}\,m}=32\times10^{-3}\,Nm^{-1}=0.032\,Nm^{-1}. Hence the SI value is .
The surface tension of mercury is . Its value in SI units is
32\,dyne\,cm^{-1}=\dfrac{32\times10^{-5}\,N}{10^{-2}\,m}=32\times10^{-3}\,Nm^{-1}=0.032\,Nm^{-1}. Hence the SI value is .