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JEE Main Physics question

PhysicsUnits and MeasurementJEE Main

The thrust developed by a rocket-motor is given by , where is the mass of the gas ejected per unit time, is velocity of the gas, is area of cross-section of the nozzle, are the pressures of the exhaust gas and surrounding atmosphere. The formula is dimensionally

Answer: (A)

Solution

here is a mass flow rate, dimension , so mv=[MT^{-1}][LT^{-1}]=[MLT^{-2}], the dimension of force. Also , also force,

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Question ID VK-157192