A projectile is projected with a velocity of 20 m/s making an angle of 45° with horizontal. The equation for...

Question

A projectile is projected with a velocity of 20 m/s making an angle of 45° with horizontal. The equation for the trajectory is h=Ax-Bx^2, where h is height, x is horizontal distance, A and B are constants (g=10 ms^ -2 ). The ratio A:B is

Accepted Answer

(D)

JEE Main Physics question

Solution

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