JEE Main Physics question
A bullet of mass is fired with a velocity 50 ms⁻¹ at an angle with the horizontal. At the highest point of its trajectory, it collides head-on with a bob of mass attached to a massless string of length m, and gets embedded in the bob. After the collision, the string moves to an angle of 120°. What is the angle ?
Answer: (C)
Solution
For the bob (with the embedded bullet) to swing up to 120° from the vertical, energy conservation from the collision point to that angle gives the required post-collision speed: . With m and ms⁻²: , so ms⁻¹. At the
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account