JEE Main Physics question
A particle is projected with 200 ms⁻¹, at an angle of 60°. At the highest point, it explodes into three particles of equal masses. One goes vertically upward with velocity 100 ms⁻¹, the second particle goes vertically downward with the same velocity as the first. Then what is the velocity of the third particle?
Answer: (D)
Solution
At the highest point, horizontal velocity ms⁻¹. Total mass (equal thirds), horizontal momentum before explosion . The two vertical-velocity particles ( and ms⁻¹ vertically, mass each) contribute zero net horizontal momentum. So the third particle (mass ) must
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