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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

The moment of inertia of a sphere of mass and radius is . The radius of gyration of the sphere about a parallel axis to the above and tangent to the sphere is

Answer: (B)

Solution

I_{tangent}=\dfrac25MR^2+MR^2=\dfrac75MR^2=MK^2 \Rightarrow K=\sqrt{\dfrac75}R.

Question ID VK-158719