JEE Main Physics question
The moment of inertia of a uniform circular ring, having a mass and a radius , about an axis tangential to the ring and perpendicular to its plane, is
Answer: (A)
Solution
I_{tangent,perp}=I_{own}+MR^2=MR^2+MR^2=2MR^2.
The moment of inertia of a uniform circular ring, having a mass and a radius , about an axis tangential to the ring and perpendicular to its plane, is
I_{tangent,perp}=I_{own}+MR^2=MR^2+MR^2=2MR^2.