JEE Advanced Chemistry question

XeF2 forms …..with AsF5

(A)XeF+ cation and AsF4+
(B)XeF2- anion and AsF4+
(C)AsF4+ cation and AsF4- anion
(D)XeF+ cation and AsF6- anionCorrect

Answer: (D)

Solution

XeF2 acts as a fluoride-ion donor toward the strong fluoride-ion acceptor AsF5: XeF2 + AsF5 → [XeF]⁺[AsF6]⁻. The F⁻ removed from XeF2 is accepted by AsF5 (completing its octahedral AsF6⁻ anion),

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Question ID VK-159325