JEE Advanced Chemistry question

When Cl2 is passed through cold dil. NaOH, the products are

(A)NaCl, NaOCl and H2OCorrect
(B)NaCl, NaClO2 and H2O
(C)NaCl, NaClO3 and H2O
(D)NaCl, NaClO4 and H2O

Answer: (A)

Solution

Chlorine disproportionates in cold, dilute alkali to give chloride (Cl⁻, 0 → −1) and hypochlorite (OCl⁻, 0 → +1): Cl2 + 2NaOH(cold, dilute) → NaCl + NaOCl + H2O. Higher oxoanions such as chlorite

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Question ID VK-159346