JEE Advanced Chemistry question

CH3CH2OH on reaction with bleaching powder forms

(A)CHCl3Correct
(B)CCl3CHO
(C)CH2ClCHO
(D)CCl4

Answer: (A)

Solution

Bleaching powder first liberates chlorine and (via hydrolysis) oxidising species: CaOCl2 + H2O → Ca(OH)2 + Cl2, and Cl2 + H2O → 2HCl + [O]. The nascent oxygen oxidises ethanol to acetaldehyde, CH3CH2OH →[O] CH3CHO, which is then exhaustively

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Question ID VK-159419