JEE Advanced Chemistry question

In the following reaction, XeF2 + BrO3⁻ + H2O → BrO4⁻ + Xe + 2HF

(A)XeF2 is an oxidizing agentCorrect
(B)XeF2 is a reducing agent
(C)BrO3⁻ is oxidized to BrO4⁻Correct
(D)XeF2 is reduced to HF

Answer: (A),(C)

Solution

Xenon's oxidation state falls from +2 (in XeF2) to 0 (in elemental Xe), meaning XeF2 is reduced — and a species that is itself reduced while causing another species to be oxidised is, by definition, the oxidising agent, confirming (a) and ruling out (b). Bromine's oxidation state rises from +5 (BrO3⁻) to +7

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Question ID VK-159486