JEE Advanced Chemistry question

Chemistry Chemical Bonding and Molecular Structure JEE Advanced

Match the molecules/ions (Column-I) with their shapes (Column-II).

Column-I: (A) ClF3 (B) [PCl4]+ (C) XeF4 (D) XeO3 Column-II: (p) Square planar (q) T-shaped (r) Tetrahedral (s) Pyramidal

Codes:

(A)A-q, B-p, C-s, D-r
(B)A-r, B-p, C-q, D-s
(C)A-q, B-r, C-p, D-sCorrect
(D)A-s, B-r, C-p, D-q

Answer: (C)

Solution

ClF3 (AX3E2, sp3d hybridised with 2 lone pairs on Cl) has a T-shaped geometry (q). [PCl4]+ is isoelectronic with SiCl4 and CCl4 (sp3, no lone pair on P) and is tetrahedral (r). XeF4

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Question ID VK-159518