JEE Advanced Chemistry question
3Cl2 + xNaOH → NaCl + NaClO3 + ... , x is .
Answer: 6
Solution
This is the hot, concentrated alkali disproportionation of chlorine: 3Cl2 + 6NaOH → 5NaCl + NaClO3 + 3H2O (balancing Cl: 6 = 5+1; Na: 6 = 5+1; O: 6 = 3+3; H: 6 =
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