For Ni and Pt different IP in MJ ,mol^ -1 are given below: (IP)_1 + (IP)_2: Ni = 2.49, Pt = 2.60. (IP)_3 + (IP)_4: Ni = 8.80, Pt = 6.70. Hence

JEE Advanced Chemistry question

For Ni and Pt different IP in are given below: : Ni = 2.49, Pt = 2.60. : Ni = 8.80, Pt = 6.70. Hence

(A)Nickel (II) compounds tend to be thermodynamically more stable than platinum (II)
(B)Platinum (IV) compounds tend to be more stable than nickel (IV)
(C)Both (a) and (b) are correctCorrect
(D)None of the above is correct

Answer: (C)

Solution

The combined first and second ionisation energy (, the energy to form ) is lower for Ni (2.49) than for Pt (2.60), meaning forms more readily/is more thermodynamically accessible, supporting statement (a). The combined third and fourth

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Question ID VK-159684