JEE Advanced Chemistry question
Coordination number of Cr is six, a complex with , en and superoxide will be in the ratio to make complex
Answer: (B)
Solution
(oxalate) and en are bidentate (2 sites each), while (superoxide) is monodentate (1 site). Coordination number: . Charge balance (overall ion charge , ): $3 + x(-2) + y(0) + z(-1) =
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