Application of Derivatives questions
910 published questions with worked solutions.
- The critical point(s) of f(x) = |2-x| x^2 is(are)
- The value of x for which the function f(x) = _0^x (1 - t^2)e^ -t^2/2 ,dt has an extremum is
- Let f(x) = x^3 + 3x^2 + 3x + 2. Then, at x = -1
- The function f(x) = x^2 + x has a
- Let f(x) = (x-1)^4 (x-2)^n, n N. Then f(x) has
- If f(x) = x^3 + 4x^2 + x + 1 is a monotonically decreasing function of x in the largest possible interval (-2, -2/3) then
- The function f(x) = ^4 x + ^4 x increases if
- If f(x) = x x and g(x) = x x , where 0 < x 1, then in the interval
- The function f(x) = ^ -1 x - x is monotonically decreasing in the set
- Let f(x) = ^ -1 (x) , where (x) is m.i. for 0 < x < /2. Then f(x) is
- If f(x) = p^2 - 1 p^2 + 1 x^3 - 3x + 2 is a decreasing function of x in R then the set of possible values of p (independent of x)...
- If f(x) = (ab - b^2 - 2)x + _0^x ( ^4 + ^4 ) ,d is a decreasing function of x for all x R and b R, b being independent of x, then
- Let f(x) = x + 10x + 3x^2 + x^3, -2 x 3. The absolute minimum value of f(x) is
- Let f(x) = 43 x^3 - 4x, 0 x 2. Then the global minimum value of the function is
- Let f(x) = 6 - 12x + 9x^2 - 2x^3, 1 x 4. Then the absolute maximum value of f(x) in the interval is
- If f(x) = _0^x (t^2 + 2t + 2) ,dt, 2 x 4, then
- Let the interval I = [-1, 4] and f : I R be a function such that f(x) = x^3 - 3x. Then the range of the function is
- Let the function f(x) be defined as follows: f(x) = cases x^3 + x^2 - 10x, & -1 x < 0 x, & 0 x < 2 1 + x, & 2 x . cases Then f(x)...
- Let f(x) be a function defined as below: f(x) = cases (x^2 - 3x), & x 0 6x + 5x^2, & x > 0. cases Then at x = 0, f(x)
- The function f(x) = x^3 + x^2 + 5x + 2x will be an invertible function if belongs to
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