Electrochemistry questions
1808 published questions with worked solutions.
- The reduction potential of calomel decreases with
- A standard hydrogen electrode has zero electrode potential because
- The oxidation potential of hydrogen electrode at pH = 10
- For the cell Zn | Zn^ +2 || Cu^ +2 | Cu, if the concentration of Zn^ +2 and Cu^ +2 ions is doubled, the emf of the cell
- For the electrode reaction M^ n+ (aq) + ne^- → M(s), the Nernst equation is given by
- In Nernst equation the constant 0.0591 represents the value of
- The electrode whose potential is arbitrary fixed is called
- Adding powdered lead and iron to a solution that is 1 M in both Pb^ 2+ and Fe^ 2+ , would result in reaction in which
- What is potential of half cell containing zinc electrode in 0.01 M ZnSO_4? (E^ = -0.763 V)
- Among the following, the oxidation potential is maximum in case of :
- A cell is represented by the equation Cu(s) + 2Ag^+(aq) → Cu^ 2+ (aq) + 2Ag(s). The voltage of the cell will increase with the...
- The difference of potential between the electrode and its salt solution at equilibrium is called
- The reduction potential is the tendency of an electrode to
- If standard electrode potential of Cu^ 2+ / Cu is 0.34 V, then potential of Cu dipped in 0.1 M solution of CuSO_4 will be
- The standard reduction potential for Pb^ 2+ | Pb and Zn^ 2+ | Zn are -0.126 V and -0.763 V respectively. The e.m.f. of the cell...
- The e.m.f. of the cell depends upon
- If the standard oxidation potential, E^ for the half cell reaction are Zn → Zn^ 2+ + 2e^- ; E^ = +0.76 V and Fe → Fe^ 2+ + 2e^- ;...
- The emf for the cell Ni | Ni^ 2+ (1.0 M) || Au^ 3+ (1.0 M) | Au (E^ for Ni^ 2+ / Ni = -0.25 V; E^ for Au^ 3+ | Au = 1.50 V) is
- The cell potential for the cell Ni | Ni^ 2+ (1 M) || Cu^ 2+ (1 M) | Cu is 0.59 V and E(Cu^ 2+ | Cu) = +0.34 V. What is the...
- When zinc electrode and calomel electrode are coupled to form a cell, the cell emf is given as
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