Organic Oxidation & Reduction Reactions questions
697 published questions with worked solutions.
- A [ Zn, H _2 O ] O _3 ( CH _3)_2 CO + HCHO + OHC–CHO . A is
- Cyclopropyl–C –cyclopropyl (A, C_8H_ 10 ) O _3/ H _2 O acid B. Separately, cyclopropylmagnesium bromide (C) [ H _3 O ^+] CO _2...
- Cyclopropyl–C –CH_3 (X, 1 mol) [ H _3 O ^+] HCO _3 H A [ CH _3 COOH ] CrO _3 B Aq. KMnO _4 C. Identify the row (A, B, C) that...
- 2-Methylpent-2-ene, (CH_3)_2C=CH–CH_2CH_3, on ozonolysis gives
- (CH_3)_2C=CH–CH_2–CHO, on vigorous oxidation with hot alkaline KMnO_4, gives
- Baeyer's reagent is used in the laboratory for
- 1-Butyne, on reaction with hot alkaline KMnO_4, gives
- Reduction of a carbonyl compound to the corresponding alkane using NH_2–NH_2 and NaOH (or KOH) in a high-boiling solvent is called
- The most oxidised form of the hydrocarbon fragment R–CH_3 is
- Reduction of 2-butyne with Na in liquid NH_3 gives predominantly
- Which of the following is generally used as a reducing agent in organic chemistry?
- Reduction of 2-methyl-1-bromopropane (isobutyl bromide) with metal and acid gives
- Acetylene and ethylene react separately with cold, dilute, alkaline KMnO_4 to give, respectively,
- Ozonolysis of propyne gives
- Reaction of ethene with oxygen gas in the presence of a silver catalyst gives
- Ozonolysis of buta-1,3-diene, CH_2=CH–CH=CH_2, gives
- Ozonolysis of isobutylene (isobutene), (CH_3)_2C=CH_2, gives
- The reaction of acetylene with excess sodium hypochlorite (NaOCl) gives, after double addition/oxidation,
- R–CH=CH_2 [ C _2 H _5 OH ] Na/NH _3( l ) R–CH_2–CH_3. This dissolving-metal reduction of an alkene is called
- R_2C=O is **not** converted to R_2CH_2 by
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